Heat flow problem (copper pipe)

[BMcC]

Homework Statement

A copper bar with a cross sectional area of 4.40 cm² and a length of 0.62 m has one end at 1 °C and the other end at 97 °C. Find the heat flow through the bar if the thermal conductivity of copper is 385 W/(m·K)

Homework Equations

R = (λ*L)/A

I = ΔT / R

k = 1/λ

R = resistance
λ = thermal resistivity
L = length of pipe
A = cross sectional area

I = thermal current
ΔT = change in temperature

k = thermal conductivity

3. My attempt

So first I converted the area 4.40 cm² into 0.044 m².

Then I converted the thermal conductivity given in the problem to thermal resistivity

k = 1/λ
λ = 1/k = 1/385 W/(m·K) = 0.00259 mK/W

Using this value, the area, and the length from the problem, I used R = (λ*L)/A

R = (0.00259 mK/W)(0.62 m) / 0.044 m²
R = 0.0366 K/W

Now I plugged this R into the thermal current formula I = ΔT/R, where ΔT = 97 °C - 1 °C = 96 °C

The ΔT is measured in Kelvin, but is still a difference of 96 units.

I = 96K / 0.0366 K/W = 2622.95 W = 2622.95 J/s

This is incorrect apparently. Does anybody know where I might have went wrong?

Thanks!

 

[TSny]

Hello, BMcC. I haven't checked all of your numbers, but I did notice that you made a common mistake in converting 4.40 cm² to m².

 

[BMcC]

Ah wow how silly of me. That changes everything. Thanks TSny!