Heating coil wire resistance and length of wire required

AI Thread Summary
To determine the required resistance for a heating coil using Nichrome wire, the resistance is calculated as R = V/I, yielding approximately 12.973 Ohms for a current of 9.25 A at 120 V. The length of the wire needed is derived from the formula R = ρl/A, where ρ is the resistivity and A is the cross-sectional area. The correct area calculation is crucial, as the initial attempt led to an incorrect length of 255 m. After clarification on the formulas and units, the proper calculations should yield accurate results. Understanding the relationship between resistance, resistivity, and wire dimensions is essential for accurate heating coil design.
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Homework Statement


A portion of Nichrome wire of radius 2.50 mm is to be used
in winding a heating coil. If the coil must draw a current of
9.25 A when a voltage of 120 V is applied across its ends,
find (a) the required resistance of the coil and (b) the
length of wire you must use to wind the coil.


Homework Equations


RI = V
R = I/oA



The Attempt at a Solution


(a) RI = V
R = V/I = 120V/9.25A = 12.973Ohms

(b)
R = l/oA
l = RoA = (12.973Ohms)(.000001ohms*m)(.0025m*3.14*2) = 2.036761e-7m

The answer to the second part of the equation is 255m and I can't figure out what I did wrong...

Thanks!
 
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Your units aren't working out well--equation for resistance seems odd.

Try R=ρl/A

ρ, resistivity in Ωm
l, length in m
A, cross-sectional area in m2.
 
Did you use the correct formula for area? Did you use a value for resistivity or conductivity for the symbol "o"?
 
Ah OK, that worked. I am not sure why the other formula from the book didn't show that but maybe I missed something... Thanks!
 
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