Help design torque, power needed

AI Thread Summary
The discussion focuses on designing a transmission for an off-road car, specifically calculating the torque and power needed to move a 550 lbs load at a constant speed of 35 mph. The user has determined the total frictional force opposing the motion to be 815.21 N, which is essential for calculating power using the formula Power = Force X Velocity. To find the necessary torque, the relationship Power = Torque X Angular velocity is highlighted, with angular velocity derived from linear velocity and gear ratios. Additionally, the conversation touches on the need to calculate average torque for acceleration from rest to the target speed. Understanding these calculations is crucial for effective transmission design.
tebrown3
Messages
5
Reaction score
0
I am designing a transmission for my class but i have a couple of concepts i kinda confused, i have a 550lbs load, and i want to move 35mph=15.64m/s at a constant speed, assuming the drag coefficient to be Cd=.55 and the coefficient of rolling resistance to be Crr=.3 (tires on sand), i found out the two frictional forces going against a rigid body(my off road car) which are the sum of the Rolling resistance force and the force of aerodynamic drag which turned our to be F=815.21 N, i want to like to learn how to find the torque necessary to move it and the power required, do we keep power constant?, and does the power depend on torque or vice versa? Thanks in advance
here are the eqn used

http://upload.wikimedia.org/math/2/8/5/28560fb9ccae7b5f811de11f965d5478.pnghttp://upload.wikimedia.org/math/9/a/b/9ab71e6e4f97b6a9d63cfa5aded81f1a.png
 
Last edited:
Engineering news on Phys.org
Note that:

Work = Force X Distance

Power = Work / Time = Force X Distance / Time

Velocity = Distance / Time

Thus,

Power = Force X Velocity

You can compute your power from the 815 N force you figured and your 35 mph velocity.

Then the power and torque are related as:

Power = Torque X Angular velocity

And you can find the angular velocity from linear velocity and gear ratios.
 
thank you that cleared up alot, but how do you calculate the power and torque needed when the car is at rest to 35 mph?
 
Last edited:
Compute Power = Force X Velocity from your numbers above.

Then look at your engine rpm at 35 mph. Use the transmission gear ratio to find the transmission rpm. Using this power and rpm, figure the transmission torque.
 
edgepflow said:
Compute Power = Force X Velocity from your numbers above.

Then look at your engine rpm at 35 mph. Use the transmission gear ratio to find the transmission rpm. Using this power and rpm, figure the transmission torque.

To calculate the rate of acceleration don't we need to know the average torque? That is from rest (to get the load moving) through the engines rpm range to 35 mph. Which would be calculated as a function F(x) torque (or maybe F(x) power)?

Willy
 
To calculate the rate of acceleration don't we need to know the average torque? That is from rest (to get the load moving) through the engines rpm range to 35 mph. Which would be calculated as a function F(x) torque (or maybe F(x) power)?

Willy
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Thread 'What's the most likely cause for this carbon seal crack?'
We have a molded carbon graphite seal that is used in an inline axial piston, variable displacement hydraulic pump. One of our customers reported that, when using the “A” parts in the past, they only needed to replace them due to normal wear. However, after switching to our parts, the replacement cycle seems to be much shorter due to “broken” or “cracked” failures. This issue was identified after hydraulic fluid leakage was observed. According to their records, the same problem has occurred...
Back
Top