How Do You Calculate Average Volume Charge Density in a Layer of Air?

AI Thread Summary
To calculate the average volume charge density in the layer of air between 500 m and 600 m, apply Gauss' law using the electric field values of 150 N/C and 80 N/C. The net electric field change across the 100 m height is essential for determining the charge density. The charge per unit volume can be derived from the difference in electric field strengths at the two altitudes. The vertical surfaces of the Gaussian surface can be ignored since the electric field is horizontal, simplifying the calculation. The average volume charge density is ultimately expressed in C/m^3 based on these parameters.
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In the air over a particular region at an altitude of 500 m above the ground, the electric field is 150 N/C directed downward. At 600 m above the ground, the electric field is 80 N/C downward. What is the average volume charge density in the layer of air between these two elevations?

the answer is supposed to be in C/m^3. i have looked at this question for a long time now and can not find a way to solve it. i think this problem would be easier if the volume of the slab of air of 100m height can be calculated and then use Gauss' law. but other then that i can not think of any other way to solve it. can anyone help me?
 
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kevinf said:
In the air over a particular region at an altitude of 500 m above the ground, the electric field is 150 N/C directed downward. At 600 m above the ground, the electric field is 80 N/C downward. What is the average volume charge density in the layer of air between these two elevations?

the answer is supposed to be in C/m^3. i have looked at this question for a long time now and can not find a way to solve it. i think this problem would be easier if the volume of the slab of air of 100m height can be calculated and then use Gauss' law. but other then that i can not think of any other way to solve it. can anyone help me?

Well that is what you want to do isn't it?
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/gaulaw.html#c2

Apply Gauss Law. Say you have a 100 x 1 cubic meter closed surface with field lines only going through 2 surfaces - top and bottom.

Isn't the net flux the charge inside, and the charge per cubic meter would be 100th of that?
 
so should i just kind of make up a volume since it apparently isn't important?
 
kevinf said:
so should i just kind of make up a volume since it apparently isn't important?

It does make a difference.

The only information you are given are for the horizontal surfaces at 500m and 600m. You can ignore the vertical surfaces because the dot product of the E field and the vertical is 0.

You have 150/m2 at the bottom and 80/m2 at the top.
 
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