Engineering How Do You Calculate Voltages and Power in a Complex Circuit?

AI Thread Summary
The discussion focuses on calculating voltages and power in a complex circuit involving resistors. The voltages v1 and v2 across the 30Ω and 5Ω resistors were found to be 3V and 0.5V, respectively. The equivalent resistance for the parallel resistors was simplified to 6Ω, leading to a total current of 0.5A. Using the current divider rule, the individual currents through the resistors were determined, resulting in the calculated voltages. The power dissipated in the 6Ω resistor was calculated to be 1.5W, confirming the accuracy of the solution.
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Homework Statement


(a) Find v1 and v2 in the following circuit. ( i assume that they are asking for voltage of 30Ω and 5Ω)
(b) Determine the power dissipated in the 6-Ω resistor.
https://sphotos-b.xx.fbcdn.net/hphotos-ash3/580277_498142810205239_1717053686_n.jpg

Homework Equations


Equivalent resistor equation.
Current divider

The Attempt at a Solution


simplified the 3 parallel resistors into Req = 6Ω
Find Is = 12V/ (12+6+6) = 0.5A
Back to original circuit, 30Ω || 25+5Ω => Req2 = 15Ω
Use current divider rule to find Current of eq2 = (10Ω x 0.5A)/(10+15Ω) = 0.2A

Use that to find I1 = 0.1A and I2=0.1A

so V1 = 0.1 x 30 = 3V
V2 = 0.1 x 5 = 0.5V

P = Is^2 x 6Ω = 1.5WTHanks for your time.
 
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