How Do You Find Tension in Two Cables Holding a 200 kg Weight?

AI Thread Summary
To find the tension in two cables holding a 200 kg weight, the x-components of the tension must sum to zero, while the y-components must equal the weight. The initial equations presented by the user indicate an attempt to resolve the forces but lack clarity and specific angle information. There is a concern that the values used do not adhere to the Pythagorean identity, as the squares of the sine and cosine components should equal one. Additional details, such as the angles of the cables, are necessary for a complete solution. Clearer equations and accurate values are essential for determining the correct tension in the cables.
stacy123
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how do you find tension in two cables set against a wall will holding a weight of 200 kg up


The Attempt at a Solution


ƩFx: 0.86Fad +0.72Fac=0
ƩFy: -0.37Fad + -0.64Fac = -1960

Homework Statement

 
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You haven't provided enough information. You need to give us the *exact* problem statement (verbatim). I can't evaluate whether your attempt at a solution is a good start if I don't even know what numbers you have been given.

The general idea that the x-components should sum to zero and the y components should together be equal and opposite to the weight is correct.
 
http://https://bay167.mail.live.com/att/GetAttachment.aspx?tnail=0&messageId=3dfae626-3d1b-11e3-8d8f-002264c17d58&Aux=2354|0|8D09F3F28148770||0|1|0|0|7|5,11,53&cid=e8972162f752523d&maxwidth=220&maxheight=160&size=Att
 
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Unfortunately, your image doesn't show up. Can you just tell me the angle of each wire from the vertical (or from the horizontal)? And, can you write down your solution in more detail, so that instead of having a bunch of "magic numbers" in it, it's more clear where you are getting those numbers from?
 
Stacy,

It doesn't seem like your equations can be correct. The 0.86 and the 0.37 are supposed to represent the sine and cosine of a certain angle, but the sum of their squares does not add up to 1. The same goes for the 0.72 and the 0.64.

Chet
 
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