How Much Pressure Is Required to Compress an Iron Block by 0.16%?

Thread starter zyphriss2
Start date Oct 27, 2008
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Iron Pressure

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To compress an iron block by 0.16%, a specific pressure or stress is required, which can be calculated using the relationship between stress and strain. Stress is defined as force divided by the cross-sectional area (csa), while strain is the change in length divided by the original length. Young's modulus for iron is essential for this calculation, as it relates stress to strain. The discussion emphasizes the need to reference Young's modulus values to determine the exact pressure in N/m². Understanding these relationships is crucial for accurately calculating the required pressure.

Oct 27, 2008

zyphriss2

How much pressure is needed to compress the volume of an iron block by 0.16 \%? Express your answer in {\rm{N/m}}^2.

I know pressure is the same as stress, and that stress is force/csa. Could someone point me in the right direction.

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Oct 28, 2008

Redbelly98

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Look up the relation between stress and strain.

Also, you will need the value of Young's modulus for iron.

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