How to calculate the Work (Joules) of lifting a book

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Homework Help Overview

The discussion revolves around calculating the work required to lift a stack of books, specifically focusing on the potential energy involved in lifting multiple books to a certain height. The original poster attempts to apply the formula for potential energy but arrives at a different result than the provided answer key.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster calculates the work for each book based on their mass and height, questioning the discrepancy between their result and the answer key. Some participants suggest potential errors in the problem statement, such as unit inconsistencies.

Discussion Status

Participants are exploring the calculations and questioning the assumptions made in the problem setup. There is a suggestion that the answer key may contain a typo, but no consensus has been reached regarding the correct interpretation of the problem.

Contextual Notes

There is mention of mixed units in the problem statement, which may affect the calculations. The original poster's calculations are based on centimeters, while SI units are preferred.

Alyssa Eiger
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1. I'm trying to calculate work it takes to lift 4 books, and stack them on top of each other in a 20 cm high stack. The problem reports:
- 5 books are lying on the ground. They are each: 2kg, 4cm thick.


Using the formula for Potential Energy (mgh), my calculations reflect it takes 8J:
- Book 1 is already on the ground.
- Book 2 on Book 1: (2kg)*(10m/s^2)*(.04m) = 8 J
- Book 3 on Book 2: 1.6 J
- Book 4 on Book 3: 2.4 J
- Book 5 on Book 4: 3.2 J

Thus, I get 8J - however the answer key to the problem reports it's 80J. Am I missing a critical component?

Any input is appreciated.
 
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UPDATE: this should read: "- Book 2 on Book 1: (2kg)*(10m/s^2)*(.04m) = .8 J"
 
Hi Alyssa Eiger,

Welcome to Physics Forums!

In future, please retain formatting template in your post. Don't delete or write over it. Thanks.

Your work looks good and the result fine. Perhaps the answer key has a typo and should read "8.0 J".
 
gneill said:
Hi Alyssa Eiger,

Welcome to Physics Forums!

In future, please retain formatting template in your post. Don't delete or write over it. Thanks.

Your work looks good and the result fine. Perhaps the answer key has a typo and should read "8.0 J".
Thank you GNeill. I will be sure to keep formatting in the future.
AE
 
I have not checked your arithmetic, but one potential difficulty is in the problem statement itself. It uses mixed units. Centimeters are not SI units; this data needs to be converted to meters to have any prospect of a correct result. This is a flaw in the way the problem is posed, not in the OP solution.
 

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