1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Ideal Gas Law Equilibrium Requirements

  1. Jun 30, 2015 #1
    It is well known that the ideal gas law applies only to an ideal gas, one consisting of particles infinitesimal in size and exhibits no interactions between the particles. Considering an ideal gas, is the ideal gas law valid under non-equilibrium conditions? For example, does the ideal gas law hold for all instants of in the free expansion of an ideal gas?

    References, if available, would be appreciated.
  2. jcsd
  3. Jun 30, 2015 #2
    "Free"expansion? How do you define volume for such a condition? PV = MRT is then not valid.
    The Maxwell-Boltzman distribution is not valid either. Lets assume the expansion of a Ne
    gas volume starts from an initial equilibrium state. At say 20 C the Ne atoms have an average
    velocity of ~850m/s, but there are atoms with velocities close to 0 m/s and some which
    move at over 2000 m/s. Clearly in a "free" expansion the velocity distribution at the boundaries of the
    expanding Ne cloud will not be Maxwellian.
  4. Jun 30, 2015 #3
    Kazys, thank you. But why is it that "the velocity distribution at the boundaries of the gas will not be Maxwellian" in a "free" expansion?
  5. Jul 2, 2015 #4
    My answer is simplistic, and because of that chances are that it is correct. Consider the Ne cloud before its free expansion. Within the could
    the molecules interact, the probability is that fast ones loose energy, slow ones gain it. Equilibrium is maintained. At the edges the fast
    molecules move faster in all directions including the outward directions. There they do not interact but keep moving. The slow ones
    tag behind. Consequently the ratio of fast to slow molecules changes, thus it is no longer Maxwellian.
  6. Jul 2, 2015 #5
    Thanks Kazys - this makes sense. As an aside, you are referring to Occam's razor, when you say the simple answer is usually the correct one, right?
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Ideal Gas Law Equilibrium Requirements
  1. Ideal gas laws (Replies: 3)