Incline plane and static friction

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SUMMARY

The discussion centers on calculating the coefficient of static friction for a block on an inclined plane that begins to slide at an angle of 23°. The relevant equation used is the relationship between the coefficient of static friction (u(s)) and the tangent of the sliding angle, expressed as u(s) = tan(θ). By substituting the angle θ with 23°, the coefficient of static friction is determined to be approximately 0.4244.

PREREQUISITES
  • Understanding of static friction and its equations
  • Knowledge of inclined plane mechanics
  • Familiarity with trigonometric functions, specifically tangent
  • Basic physics concepts related to forces and motion
NEXT STEPS
  • Study the derivation of the static friction equation F(static friction) = u(s) Fn
  • Explore the role of angles in inclined plane problems in physics
  • Learn about the differences between static and kinetic friction
  • Investigate real-world applications of static friction in engineering
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding the principles of friction on inclined surfaces.

linnus
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Homework Statement



A block sits on an inclined plane, which is slowly being raised. The block remains motionless until the angle the plane makes with the horizontal is 23°. At this angle, the block begins to slide down the plane. What is the coefficient of static friction between the plane and the block?

Homework Equations



F(static friction)= u(s) Fn
mgsin(23)= x component
mgcos (23)= y component
F=ma

The Attempt at a Solution



I don't know where to even start since it doesn't give me a mass or weight...
 
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This angle at which the block just starts to slide is called sliding angle. What is the relation between the tangent of sliding angle and coefficient of static friction?
 
coefficient of static friction=tan (x)
oh..so the answer is tan (23)=.4244
Thanks!
 

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