Incline plane and static friction

AI Thread Summary
The problem involves a block on an inclined plane that begins to slide at an angle of 23°. To find the coefficient of static friction, the relationship between the tangent of the sliding angle and the coefficient is utilized, expressed as coefficient of static friction = tan(23°). The calculated coefficient of static friction is approximately 0.4244. The discussion highlights the importance of understanding the forces acting on the block and the concept of the sliding angle. This analysis provides a clear method for determining static friction in inclined plane scenarios.
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Homework Statement



A block sits on an inclined plane, which is slowly being raised. The block remains motionless until the angle the plane makes with the horizontal is 23°. At this angle, the block begins to slide down the plane. What is the coefficient of static friction between the plane and the block?

Homework Equations



F(static friction)= u(s) Fn
mgsin(23)= x component
mgcos (23)= y component
F=ma

The Attempt at a Solution



I don't know where to even start since it doesn't give me a mass or weight...
 
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This angle at which the block just starts to slide is called sliding angle. What is the relation between the tangent of sliding angle and coefficient of static friction?
 
coefficient of static friction=tan (x)
oh..so the answer is tan (23)=.4244
Thanks!
 

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