Integration of Function of Two Variables

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Homework Help Overview

The discussion revolves around integrating a function of two variables, specifically the integral \(\int (z^2 + x^2)^{-3/2} dx\). The original poster expresses uncertainty due to a lack of exposure to this topic in their calculus classes.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the concept of integrating functions of two variables and discuss potential methods, including trigonometric substitution. Questions arise regarding the derivation of specific terms in the integral's result.

Discussion Status

Some participants have suggested approaches such as trigonometric substitution, while others are attempting to understand the components of the integral's result. There is an acknowledgment of the challenges faced in grasping the integration process.

Contextual Notes

The original poster notes that \(z^2\) is a constant with respect to \(x\), which may influence the integration process. There is also a mention of the original poster's limited experience with the topic, which shapes the discussion's direction.

PeterFer
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Homework Statement




For one of my physics classes I need to integrate a function of two variables, but I haven't learned how to do it yet in my calculus classes. If anyone could explain to me how to do it, it would be much appreciated. It's probably pretty simple I just haven't learned it yet.

the integral is [tex]\int[/tex] (z 2 + x2)-3/2 dx



and i know that the answer is x/ sqrt (z2 + x2) z2


thanks
 
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PeterFer said:

Homework Statement




For one of my physics classes I need to integrate a function of two variables, but I haven't learned how to do it yet in my calculus classes. If anyone could explain to me how to do it, it would be much appreciated. It's probably pretty simple I just haven't learned it yet.

the integral is [tex]\int[/tex] (z 2 + x2)-3/2 dx

and i know that the answer is x/ sqrt (z2 + x2) z2


thanks

z^2 is a constant with respect to x. That might help.
 
yea I've been trying to think of it that way but everything i do doesn't end up working and I can't think of anything else to do
 
You can make a trig substitution.
 
I think I understand where the sqrt(z2 + x2) in the denominator of the answer comes from, if you pretend z2 + x2 is one term and take its anti-derivative you get 1/sqrt(z2 + x2), but i don't know where the x in the numerator or the z2 in the denominator come from
 
What happens if you make x= ztan[tex]\theta[/tex].
 
╔(σ_σ)╝ said:
What happens if you make x= ztan[tex]\theta[/tex].

oh wow thank you so much, I completely forgot about trig substitution. Thanks a lot I just got it
 

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