Interesting Electric Field and Spring Problemf

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SUMMARY

The discussion centers on a physics problem involving a block with mass m and charge +Q connected to an insulating spring with spring constant k, placed in a uniform electric field of magnitude E. The maximum expansion of the spring is determined to be 2QE/k, while the equilibrium position of the block is at x = QE/k. The block's motion is confirmed to be simple harmonic, with the period derivable from the spring constant and mass. The problem also explores the effects of kinetic friction on the system.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with concepts of electric force and potential energy
  • Knowledge of simple harmonic motion principles
  • Basic grasp of friction and its effects on motion
NEXT STEPS
  • Study the derivation of potential energy in springs and electric fields
  • Learn about simple harmonic motion and its mathematical representation
  • Investigate the effects of kinetic friction on oscillatory systems
  • Explore the relationship between force, mass, and acceleration in electric fields
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Students in physics, particularly those studying mechanics and electromagnetism, as well as educators looking for examples of electric fields and harmonic motion in practical applications.

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Homework Statement


A block having mass m and charge +Q is connected to an insulating spring having constant k. The block lies on a frictionless, insulating horizontal track, and the system is immersed in a uniform electric field of magnitude E as shown in the diagram. If the block is released from rest when the spring is unstretched (at x = 0),

(a) by what maximum amount does the spring expand?
(b) what is the equilibrium position of the block
(c) show that the block's motion is simple harmonic and determine its period
(d) repeat (a) assuming that the coefficient of kinetic friction between the block and the surface is mew K.

http://img513.imageshack.us/img513/3959/physprobzm4.png

Homework Equations


a few, F = qE = ma = -kx

The Attempt at a Solution



I'm only starting to attempt part (a), the block has a force QE to the right and a restoring force kx to the left.

So I equated the forces thus: QE = kx and solved for x to obtain x = QE/k.

This isn't the solution for (a), but it is for (b). The solution for (a) is 2QE/k

It's driving me crazy trying to find where the 2 came into calculations. Working backwards from (b) I see that the equilibrium position is half of the maximum expansion. But how so?
 
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Right, that's the answer for B because at the equilibrium position, the restoring force of the spring is equal to the electric force. That's why at equilibrium, Fnet is 0 so the acceleration of the block is also zero.

For part A, consider the relationship between the potential energy of the spring at the point of furthest expansion and the work the electric force must do to get the block to that point.
 

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