Is Every Differential 1-Form on a Line the Differential of Some Function?

Abhishek11235
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Homework Statement


This problem is from V.I Arnold's book Mathematics of Classical Mechanics.
Q) Show that every differential 1-form on line is differential of some function

Homework Equations


The differential of any function is
$$df_{x}(\psi): TM_{x} \rightarrow R$$

The Attempt at a Solution



The tangent to line is line itself. The differential 1-form is ##dy-dx=0##. Here I am struct. I don't know how to find out the differential. Can anyone help?
 

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Abhishek11235 said:
The tangent to line is line itself.
No.

Abhishek11235 said:
The differential 1-form is dy−dx=0dy−dx=0dy-dx=0.
No. A general differential 1-form is of the form ##\omega = g(x) dx##. You have to show that there exists a function ##G(x)## such that ##\omega = dG##.
 
Orodruin said:
No.No. A general differential 1-form is of the form ##\omega = g(x) dx##. You have to show that there exists a function ##G(x)## such that ##\omega = dG##.

That means I have to integrate. Can you provide me solution?
 
Abhishek11235 said:
Can you provide me solution?
That would violate the forum rules, which you would realize if you had bothered reading them.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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