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Stand by, mathematics in progress.
 
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If I recall correctly, because both expressions are of the same power: ^1/2, I can combine them without any issue, correct?
 
ArmChairPhysicist said:
If I recall correctly, because both expressions are of the same power: ^1/2, I can combine them without any issue, correct?

Combine them how? If you mean [itex]\sqrt(a) + \sqrt(b) = \sqrt(a + b)[/itex], then no, you can't do that.
 
So I have
(7^2 + X^2)^1/2 + (21^2 + (120-x)^2)^1/2 as the total length
 
ArmChairPhysicist said:
So I have
(7^2 + X^2)^1/2 + (21^2 + (120-x)^2)^1/2 as the total length

Correct. Good job. Now use calculus to find the value of X which minimizes the length.
 
I can expand (120-x)^2 into its polynomial and combine within the expression,
 
Ok, now the chain rule
 
If I did it right
AF' is

2x/(2(7^2+X^2)^1/2)
 
When taking the derivative of the DF expression, is it best to expand (120-X)^2 before taking the derivative?
 
I have this now for DF'
282-2X / 2(21^2 +(120-X)^2)^1/2
 
Then I simplify those, set them to zero and solve I believe?
 
Could I square the fractions to eliminate the radicals?
 
If not how should I go about simplifying what I have
 
Currently I have this by cross multiplying out the denominators.
X•sqrt(21^2 +(120-X)^2) +
(141-X)•sqrt(7^2+X^2)=0
 
image.jpg

This is my current equation, and is what I'm attempting to simplify.

I know that my end goal is to isolate X so I can solve, but I need to eliminate those radicals, and I can't figure out how. Any ideas?
 
ArmChairPhysicist said:
View attachment 196037
This is my current equation, and is what I'm attempting to simplify.

I know that my end goal is to isolate X so I can solve, but I need to eliminate those radicals, and I can't figure out how. Any ideas?

Rewrite the derivative by combining the terms over the common denominator ##D = \sqrt{7^2+x^2} \sqrt{21^2+(120-x)^2}##. That will produce a numerator having the square roots in two terms. Now equate the numerator to zero, using the standard approach, which is to re-write the equation so that the two square-roots are on opposite sides; then square both sides. That gets rid of all the square roots.
 
Last edited:
ArmChairPhysicist said:
View attachment 196037
This is my current equation, and is what I'm attempting to simplify.

I know that my end goal is to isolate X so I can solve, but I need to eliminate those radicals, and I can't figure out how. Any ideas?

I would check where that '141' in the numerator came from.
 
The 141 came from me taking the derivative of 21^2+(120-x)2

2 • 21 ^2-1 =
42

(120-x)^2 = 2(120-X)^1 correct?
 
Then when I reduced the fractions in my equation 282-2x became 141-x unless I messed up somewhere
 
So from this
 

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Cancel out the denominator, then square both sides?
 
image.jpg
Which gets me this.
 
ArmChairPhysicist said:
View attachment 196047 To this?
Well, the answer is yes, since you have done exactly what I suggested. However: please do not continually ask questions as to whether your next step is correct or not---just work it all out, from beginning to the end (or, at least, as FAR as you can). Try to develop some confidence in your own work.
 
Now I simply solve for x?
 
Thank you so much for your help and time.
 
ArmChairPhysicist said:
The 141 came from me taking the derivative of 21^2+(120-x)2

2 • 21 ^2-1 =
42

(120-x)^2 = 2(120-X)^1 correct?

Not correct. The derivative of ##21^2## is zero. It's a constant.