Maclaurin Series expansion of Lorentz factor

[MarekS]

Homework Statement

Wikipedia states that the Maclaurin Series expansion of the Lorentz factor is http://en.wikipedia.org/wiki/Lorentz_factor"

Homework Equations

Relevant equations are all found in that article

The Attempt at a Solution

I don't see how this comes about. My attempt: 1+0+1/2+...

How can beta be in the expansion, when it should be substituted by 0, since the Maclaurin Series is about 0?

 

[dx]

The maclaurin series of a function about zero is f(x) = f(0) + f'(0)x + f''(0)x²/2! + ...

 

[Cyosis]

The Maclaurin series about 0 is given by:

\gamma(\beta)=\gamma(0)+\beta \gamma'(0)+\frac{\beta^2}{2!}\gamma''(0)+...

Try it out.

 

[MarekS]

Yes, thanks. I found my error: I didn't notice the factors (beta) in the terms.