Magnetic Fields and the Biot-Savart Law

DragcoDavid
Messages
1
Reaction score
0
Hi, I'm new here but been looking to you guys for solutions for a while now. However, I cannot find the kind of solution on here already, so I thought I'd put it out here.

My main problem with physics is always just finding the formulas I need. If you can at least point me in the right direction with the right formula(s), I'll be most grateful.

Homework Statement


The magnetic field 35.0 cm away from a long, straight wire carrying current 7.00 A is 4.00 µT.

(a) At what distance is it 0.300 µT?
466.6667 cm

(b) At one instant, the two conductors in a long household extension cord carry equal 7.00 A currents in opposite directions. The two wires are 3.00 mm apart. Find the magnetic field 35.0 cm away from the middle of the straight cord, in the plane of the two wires.

? nT

(c) At what distance is it one tenth as large?

? cm

(d) The center wire in a coaxial cable carries current 7.00 A in one direction, and the sheath around it carries current 7.00 A in the opposite direction. What magnetic field does the cable create at points outside?

? nT

Homework Equations


B= µ0*I / 2*pi*r, where µ0 is 4*pi x 10^-7, I is current in A, and r is distance in meters.

I'm sure there are others, but if I knew them, I'd wouldn't be here.

The Attempt at a Solution



Part A)
B = µ0*I / 2*pi*r
(3e-7 T) = (12.56637e-7)*(7 A) / 2*(3.14159...)*r
r = (12.56637e-7)*(7 A) / 2*(3.14159...)*(3e-7 T) = 14/3 m = 4.6667 m = 466.6667 cm

Part B) ? No idea where to start... I thought the 2 opposite forces would cancel each other out, but not totally it seems. It asks the answer in nano-tesla, so I assume that there is some canceling out here.

Part C) Extension of part B, asking where the field is 1/10th the field is in part B.

Part D) Seems similar to part B, but you tell me.
 
Physics news on Phys.org
Actually, it seems to me as if you are supposed to use Ampere's Law.

b) the cords actually want to push apart, try it out using the right hand rule.

c) plug and chug

d) definitely a question for ampere's law
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top