Engineering Mesh Analysis for Circuit: Finding ix with Supermesh

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To find ix in the given circuit, supermesh is not necessary; instead, three loop equations with three unknowns should be used. Mesh analysis typically focuses on voltages, while the presence of a dependent current source requires careful consideration. The currents i3 and ix are distinct, but ix can be expressed in terms of the mesh currents. Specifically, the relationship can be established by summing the currents at the node: I_X = I_2 - I_3. This approach allows for a clear calculation of ix using mesh analysis principles.
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Homework Statement



About this circuit:

http://oi54.tinypic.com/eqwktd.jpg

If I were to find ix. Would I be using supermesh?


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The Attempt at a Solution

 
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No. You would just write three loop equations with three unknowns. Mesh analysis wants voltages, and that is a dependent voltage source that relies on a current. You traditionally need to use supermesh when you need to work around a current source (either dependent or independent).
 
In the last mesh, aren't i3 and ix separate currents ? Or ix= i3?
 
J.live said:
In the last mesh, aren't i3 and ix separate currents ? Or ix= i3?

They are different currents, but I_x can be written in terms of your mesh currents. Just sum the currents entering and exiting that node:

I_2 -I_3 - I_X = 0 \to I_X = I_2-I_3
 
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