Metal rod rotating in magnetic induction.

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SUMMARY

The discussion focuses on calculating the number of revolutions made by a metal rod of length 1/sqrt(pi) m, rotating in a magnetic field of 5*10^-3 T, with an induced EMF of 1.5 mV. The key equation utilized is Faraday's law, specifically EMF induced = -d∅/dt. Participants suggest using the relationship between linear velocity and angular velocity, where v = ωx, to derive the total induced EMF through integration. The solution involves determining the angular velocity (ω) to find the number of rotations per second.

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  • Understanding of Faraday's law of electromagnetic induction
  • Knowledge of angular velocity and linear velocity relationships
  • Basic calculus for integration
  • Familiarity with magnetic induction concepts
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Homework Statement


A metal rod (1/sqrt(pi)) m long rotates about one of its ends in a plane perpendicular to magnetic induction of 5*10^-3 T. Calculate the number of revolutions made by the rod if EMF induced between the ends of the rod is 1.5 mV.

I have been thinking about this problem for a long time but in vain. I just don't understand where to start.Any help will be appreciated.
Thanks

Homework Equations


Faraday's law : EMF induced=- d∅/dt

The Attempt at a Solution


I have been thinking about this problem for a long time but in vain.
I have tried using Faraday's law but can't figure out equation for ∅. I just don't understand where to start.Any help will be appreciated.
Thanks
 
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Consider a small element dx of the rod at a distance x from the fix end. Suppose it is moving with a velocity v in the circular orbit.
Then the induced emf in this element dε = -vBdx. Put v = ωx.
To find the total induced emf, find the integration from zero to the given length of the rod.
In the problem emf is given. Find ω, which gives you the number of rotation per second.
 
Thank you sir/madam for your help.
 

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