Moments and force -- Forces on a cantilever hole punch

AI Thread Summary
The discussion revolves around calculating the force exerted by a single pin of a cantilever hole punch when a lever is pressed down with a force of 40 N. Participants explore the relationship between the lever arm lengths and the total force applied, considering the punch creates two holes simultaneously. There is confusion about whether to multiply the force by the number of holes, leading to clarifications on how to structure the equation correctly. The final equation suggests that the total force is distributed across the two pins, requiring adjustments in calculations. Ultimately, the focus is on understanding the mechanics behind the force distribution in the hole punch operation.
radaway
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Homework Statement


sam makes a punch hole with the perforater( two holes ). She presses the lever at A down with a force of 40 N. Calculate the total force which a single pin presses on the paper.

Homework Equations


http://s6.postimg.org/yx62wbild/image.png

The Attempt at a Solution


would it be :
40 N X 5 cm = 1,1cm X 'x' ?
 
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What about the two in the number of holes ?
 
<What about the two in the number of holes>
umm.. the perforater did what it normally needs to do. punch in 2 holes at the same time.
did you mean , I multiply the r.h.s of the equation with '2' ?
 
radaway said:
Calculate the total force which a single pin presses on the paper.
is what is asked for ...
 
Post edited to remove insult
How about --

40*(5+1.1)=(2f)*1.1 , thus f=... N.
 
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What's important is that you've got it ! (almost) all by yourself !
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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