Newton's second law problem with friction

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SUMMARY

The discussion focuses on applying Newton's second law to a problem involving friction and vertical forces. The user is confused about how an upward pull affects the net force in the vertical direction, specifically regarding the relationship between normal force (Fn), gravitational force (mg), and the applied force (Fpull). The analysis reveals that pulling upward decreases the normal force, thereby reducing the frictional force opposing horizontal motion, which facilitates easier pushing of the crate. The importance of using Free Body Diagrams and proper homework formatting is emphasized for clarity and effective problem-solving.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of frictional force calculations
  • Familiarity with Free Body Diagrams
  • Basic algebra for solving equations
NEXT STEPS
  • Study the effects of applied forces on normal force and friction
  • Learn how to construct and analyze Free Body Diagrams
  • Review the concept of net force and its implications in motion
  • Explore the relationship between coefficients of friction and applied forces
USEFUL FOR

Students preparing for physics exams, particularly those studying mechanics, as well as educators looking for effective teaching strategies in problem-solving involving forces and motion.

isukatphysics69
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1. Homework Statement

i did part a,b,c but i am confused about part d.. i have a test tomorrow and will reattempt this when i wake up but i really need a hint here..so when the worker pulls upward he is decreasing the magnitude of -mg right? so if Fn and mg initially cancel each other out, when the worker pulls upward he is making it so that the acceleration in the y direction is no longer 0 correct? so netforceydirection = Fn-mg+Fpull and it is non zero?

Homework Equations

The Attempt at a Solution

 

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isukatphysics69 said:
i did part a,b,c but i am confused about part d.. i have a test tomorrow and will reattempt this when i wake up but i really need a hint here..so when the worker pulls upward he is decreasing the magnitude of -mg right? so if Fn and mg initially cancel each other out, when the worker pulls upward he is making it so that the acceleration in the y direction is no longer 0 correct? so netforceydirection = Fn-mg+Fpull and it is non zero?

the frictional force opposing the horizontal push is = coefficient of friction x R (the net reaction)
initially R= weight mg of the crate
after help say of F1 upward F1+ R = mg

so R= mg- F1 thereby reducing the frictional force = mux(mg-F1)
in the horizontal direction. so it will help him push easily
 
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You really need to use the homework template more effectively. What you've put in the problem statement belongs in the Attempt at solution section, and you should list any equations that you think are relevant to this type of problem in the Relevant equations section. See the pinned thread, Guidelines for students and helpers, for tips on how to create effective homework help requests.

An empty Attempt at solution section is a major flag to moderators to scrutinize your post to judge whether or not you've put any effort so far. Helpers, who are volunteering their expertise, shouldn't have to tease out your efforts from random places in the post.

Considering the points you've raised in your post, I am wondering whether or not you've drawn Free Body Diagrams for the scenarios. Have you done that?
 
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