Organic Chemistry - Synthesis of Lidocaine

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The discussion centers on the synthesis of lidocaine, specifically the reaction between a-chloro-2,6-dimethylacetanilide and diethylamine, which is expected to produce diethylamine-HCl crystals as a by-product. The absence of these crystals raises questions about the reaction conditions. Factors such as temperature, concentration, and the stoichiometry of the reactants are crucial in determining whether diethylamine-HCl will precipitate. In this case, diethylamine was used in excess (4 equivalents to 1 equivalent of a-chloro-2,6-dimethylacetanilide) and the reaction was refluxed for about an hour, which may have influenced the precipitation process. Without specific details on these conditions, it is challenging to ascertain why the diethylamine-HCl did not form as expected.
Sylvia
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In lab we had to synthesize lidocaine, and one of the steps involved reacting a-chloro-2,6-dimethylacetanilide with diethylamine to form lidocaine. My professor told us that diethylamine-HCl crystals would form and these would help us determine the lidocaine yield (since they form at a 1:1 mole ratio). However, I did not get any of these crystals but I was able to form lidocaine.

So my question, how is this possible? Please help.
 
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Sylvia said:
diethylamine-HCl crystals would form
Sylvia said:
I did not get any of these crystals
The by-product didn't precipitate. "Why?" Without information regarding temperature, concentration, and other such details, there's no telling what kept the diethylamine hydrochloride from precipitating.
 
Diethylamine was in excess (4 equivs to 1 equiv a-chloro-2,6-dimethylacetanilide), refluxed reaction for about an hour
 
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