Oxidising H2O2 with KMnO4: What Happens?

AI Thread Summary
Using potassium permanganate (KMnO4) to oxidize hydrogen peroxide (H2O2) results in the formation of oxygen gas (O2) and water (H2O). The process involves the transfer of electrons, where H2O2 acts as a reducing agent in alkaline conditions, leading to the generation of hydroxide ions (OH-). Conversely, in acidic conditions, H2O2 can act as an oxidizer, resulting in the production of water. The key reactions include the reduction of H2O2 to water and the oxidation of H2O2 to oxygen gas. Understanding these reactions is crucial for applications in various chemical processes.
garytse86
Messages
311
Reaction score
0
What do you get if you use KMnO4 to oxidise hydrogen peroxide?

and what happens to hydrogen peroxide if it is used as an oxidiser?

Surely the second one there are two possibilities:

1) H2O2 + 2e- --> 2OH-
2) H2O2 + 2H+ + 2e- --> 2H2O
 
Last edited:
Chemistry news on Phys.org
*deleted*...
 
Last edited:
Hydrogen peroxide may act as oxidizer (in alkalic solution) or as a reducer (in acidic solution).
 
Last edited by a moderator:
Thanks, but I want to know what hydrogen peroxide itself changes to?
 
In reduction

H2O2 + 2H+ + 2e -> 2H2O

In oxidation

H2O2 +2OH- -> O2 + 2H2O + 2e

G
 
k. so when does this happen:

H2O2 + 2e- --> 2OH-
 
Add 2H+ on both sides of equation :smile:
 
Last edited by a moderator:
Back
Top