Percent correction for Magnetic Field vs. Electric Field

AI Thread Summary
The discussion focuses on calculating the percent correction for the electric field when considering the effects of gravity on an electron's motion. Participants emphasize the need to define "percent correction" to understand what is being corrected and why. A free-body diagram is suggested to visualize the forces acting on the electron, including gravity. The equations presented show how to incorporate gravity into the voltage calculation, leading to a modified voltage equation. The conversation highlights the importance of recognizing systematic errors when determining magnetic field strength.
michaelle1991
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Hi guys,
In the photo is the problem. We set Fb =Fe to show for E then out E into the Voltage equation to get V=vlB. However, if we won;t ignore the gravity force, what is the percent correction? (Note: q =Electron)
 

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Welcome to PF;
What is the definition of "percent correction" - that will tell you how to work it out.
In the presence of gravity - draw a free-body diagram for the electron.
 
i did a little work, but idk if it is right?
 

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You missed out defining what "percentage correction" means.
What are you correcting and why?

The fbd and calculation seems OK.

qvlB = qV + mgl

So V= vlB-gl(m/q) with gravity

Without gravity: V0=vlB

If you used B=V0/vl with V0=V then you have introduced a systematic error into your equation for determining B.
 
michaelle1991 said:
Hi guys,
In the photo is the problem. We set Fb =Fe to show for E then out E into the Voltage equation to get V=vlB. However, if we won;t ignore the gravity force, what is the percent correction? (Note: q =Electron)

Please check your PMs...
 
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