Engineering Phasor circuit solving for current

AI Thread Summary
In solving the phasor circuit for current, the current source is converted to e^(j30°) and combined with other sources through source transformation. All components must operate at the same frequency as the voltage source, as the current source's frequency does not influence the impedance of capacitors and inductors. The circuit's current Ix can be calculated by analyzing each source independently, then summing the results. Each frequency must be solved separately, and solutions should be converted to the time domain before final addition. The discussion highlights the importance of recognizing resonances in L-C circuits, confirming the accuracy of the final answer.
gfd43tg
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As I am trying this problem, I convert the current source to e^(j30°). I am not sure what I should do with that. I added it to the other current source that I did a source transformation on. By the way, all the components should have the same frequency as the voltage source, right? The frequency of the current source doesn't affect the impedance of the capacitors and inductors?
 

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Here is my attempt

ImageUploadedByPhysics Forums1399361454.312838.jpg


ImageUploadedByPhysics Forums1399361474.282759.jpg
 
It's a linear circuit, so you can determine Ix due to one source (with the other source "disabled"), and then determine Ix due to the second source (after "disabling" the first).

The circuit's Ix will be the sum of those two components, which you express by simply writing a "+" sign between the two above components because they are not of the same frequency.
 
You need to solve for each frequency separately. Convert each solution into the time domain, then add in the time domain. You can't avoid converting to the time domain separately for w1 and w2 before the final addition.
 
Here is my attempt, I think he had a little trick going

ImageUploadedByPhysics Forums1399689409.371969.jpg
 
You were clever to notice the resonances of the two L-C circuits & that there is a short circuit at each frequency. And your final answer is 100% correct! Nice work.
 

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