Phasor Problem: Convert i(rt), i(ct) from i(t)

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The discussion revolves around converting current expressions i(rt) and i(ct) from the given i(t) = 0.4A cos(wt + 60) in a circuit with a resistor and capacitor. Participants emphasize the importance of understanding the circuit configuration, whether components are in series or parallel, and how this affects the phase angles of current and voltage. There is confusion about the correct representation of the voltage, with questions raised about its phase relationship with the current through the resistor. The conversation highlights the need for clarity in circuit descriptions to solve phasor problems effectively. Overall, the thread underscores the complexities of phasor analysis in electrical circuits.
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for i = 0.4A cos (wt + 60) , how do we get i(rt) =0.35A cos(wt + 30) and then i(ct) = 0.2A cos(wt+ 120) ??
 
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v = 30V (cos 30 + j sin30) is given
 
the circuit consists of capacitor and resistor
 
A good way to present a problem like this is to describe the circuit as best as you can. With your third post, it appears you have power supply V and a capacitor and resistor connected in some fashion. How is your resistor and capacitor connected?

You gave in your first post that the current thru your resistor is at a different angle \theta compared with your capacitor. Do you notice anything special about the difference between the two angles?
 
no,there is just a z and the current and voltage is given,not even a circuit.
the current for capacitor and resistor is the answer and i don't understand how they got the answer
 
There are several possible configurations between input and output, based on two components (which component, resistor or capacitor, is first) and configurations series vs parallel vs T.

Is this correct - v = 30V (cos 30 + j sin30) ? Is this at time, t=0?

or should it be 30V (cos (wt+30) + j sin (wt+30)) = 30V e j (wt+30)?

Then look at the voltage v, and see if it is phase with the current in the resistor.

Welcome to the world of complex analysis.

See also - http://en.wikipedia.org/wiki/Phasor_(electronics)

http://en.wikibooks.org/wiki/Electronics:Phasors
 
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