Physics Problem with Lifting Force and Drag Coefficient

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SUMMARY

The discussion focuses on calculating the lifting force and drag coefficient for aircraft X, designed in 2014, which has a top speed of 812 m/s and a mass of 72,000 kg. The maximum thrust-to-weight ratio is 0.44. The drag coefficient formula used is Fd = cd 1/2 ρ v² A, where ρ represents air density, v is velocity, and A is the surface area. The participant expresses confusion regarding the concept of lifting force and its relationship to weight in level flight.

PREREQUISITES
  • Understanding of basic aerodynamics principles
  • Familiarity with the drag coefficient formula
  • Knowledge of free body diagrams in physics
  • Concept of thrust-to-weight ratio in aviation
NEXT STEPS
  • Research the principles of lift generation in aircraft
  • Learn how to calculate drag coefficient with known surface area
  • Study free body diagrams and their application in analyzing forces on aircraft
  • Explore the implications of thrust-to-weight ratio on aircraft performance
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Aerospace engineering students, physics learners, and anyone interested in understanding the mechanics of flight and aircraft performance calculations.

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Homework Statement


Flying aircraft X is designed in 2014. The current model has a top speed of 812 m/s, a mass of 72,000 kg when fully loaded, and a maximum thrust to weight ratio of 0.44. Calculate the lifting force and the drag coefficient for the Quinjet when it is flying level at top speed. Assume turbulent flow.

Homework Equations


Drag Coefficient: Fd = cd 1/2 ρ v2 A

The Attempt at a Solution


I do not understand how lifting force work(teacher didn't bother to teach us before assigning the homework) and can only calculate drag coefficient given the surface area.
 
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Can you draw a free body diagram of an aircraft in level flight at constant velocity? What is the lifting force equal to?
 
billy_joule said:
Can you draw a free body diagram of an aircraft in level flight at constant velocity? What is the lifting force equal to?
Is the lifting force just equal to the weight?
 

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