Potentia Difference and Electric Potential

AI Thread Summary
To calculate the work done on a proton moving through a uniform electric field, use the formula W = F * d, where F = qE. The charge of the proton is equal to the elementary charge, approximately 1.6 x 10^-19 C. For a proton moving 2.00 cm in an electric field of 200 N/C, the work done can be calculated as W = (1.6 x 10^-19 C)(200 N/C)(0.02 m), resulting in 6.4 x 10^-21 J. The change in potential energy of the proton is equal to the work done by the field. The potential difference can be determined using the relationship V = E * d.
TheFireFox
Messages
2
Reaction score
0
A proton moves 2.00 cm parallel to a uniform electric field of E = 200 N/C. (a) How much work is done on the proton by the field? (b)What change occurs in the potential energy of the proton? (c) What potential difference did the proton move through?


I really just need help with Part A, I should be able to get through the rest alright. I'm not entirely sure what the charge of the proton would be. I know that wok is equal to the change in potential energy, which is then equal to (kq1q2)/r...but I'm not sure what the chrages would be. Help?
 
Physics news on Phys.org
The charge on the proton is the same as the charge on the electron (except it is positive), often called the "elementary charge". You can easily look up its value in your text or in Wikipedia.

V = (kq1q2)/r applies only two point charges. For this problem with the uniform E field, you really need F = qE, an electric field causes a force on a charge. From there you can find the work done quite easily.

In a uniform E field, E = V/d. This is often called the parallel plate formula because it tells how a potential across plates distance d apart causes a uniform electric field between the plates. You could use it backwards to find your part c.

Alternatively, use the definition of potential difference = (change in energy)/charge.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top