Potential energy functions of a particle

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Homework Help Overview

The problem involves calculating the potential energy function associated with a conservative force that varies with position. The force is given as Fvec = (-Ax + Bx^4)i N, where A and B are constants. The discussion includes determining the potential energy function U(x) and analyzing changes in potential and kinetic energy as a particle moves between specified positions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between force and potential energy, with one suggesting that U(x) should be derived from the integral of the force rather than a direct product. There is also uncertainty about the correct form of the potential energy function, with multiple expressions being proposed.

Discussion Status

The discussion is ongoing, with participants exploring different formulations of the potential energy function. Some guidance has been offered regarding the integration of force to find potential energy, but there is no explicit consensus on the final expression for U(x).

Contextual Notes

Participants are working under the assumption that U = 0 at x = 0 and are considering the implications of varying force over the range of x. There is also a focus on ensuring coefficients are accurately rounded to three significant figures.

ramenmeal
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Homework Statement



A single conservative force acting on a particle varies as Fvec = (-Ax + Bx4)i N, where A and B are constants and x is in meters. Accurately round coefficients to three significant figures.
(a) Calculate the potential energy function U(x) associated with this force, taking U = 0 at x = 0. (Use A, B, and x as appropriate.)

(b) Find the change in potential energy and change in kinetic energy as the particle moves from x = 1.80 m to x = 3.40 m. (Use A, B, and x as appropriate.)

Homework Equations



w = f x d

The Attempt at a Solution



ive only attempted part a since i think i will need it to go on to part b.

w = f x d
f = (-Ax + Bx4)
d = x

PE = (-Ax + Bx^4)x = -Ax^2 + Bx^5
 
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Since the force is continuously variable over the range of x isn't your U(x) the integral of the Force F(x) and not just the product of x and F(x)?
 
oh yeah.. so should it be

(-1/2)Ax^2 + (1/4)Bx^5 ?

i'm not sure what form my final answer should be.
 
ramenmeal said:
oh yeah.. so should it be

(-1/2)Ax^2 + (1/4)Bx^5 ?

i'm not sure what form my final answer should be.

How about -1/2Ax2 + 1/5Bx5 instead?
 

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