Finding the Distance for a Projectile to Land on a Moving Cart

In summary: For example, if the height of the building was increased, would the ball hit the cart at a different location? I don't see how the height of the building is relevant in this case. The height of the building would be used to calculate the total time the ball was in the air.x/v1 = d-x/v2.
  • #1
judas_priest
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Homework Statement


A ball is kicked horizontally with speed v1 from the top of a building of height h. A small cart is moving towards the building with a constant speed v2. Right at the instant when the ball is kicked, the cart is at a distance d from the building. What is the distance d so that the ball lands right on top of the cart? You can neglect the dimensions of the cart with respect to the height of the building h. Express your answer in terms of some or all of the variables h, v1, v2 and g


Homework Equations





The Attempt at a Solution



I tried to equate the time taken (since they meet at the same time). I made sure to include 'd' in my equation, because that's the variable needed to be found

Here's my equation.

x/v1 = d-x/v2.

Where x is the distance traveled by the ball in x direction and d-x is the distance traveled by the cart.

The questions needs an 'h' in the answer. I can't get the term in my answer
 

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  • #2
Hmm, the way I see this problem is you first need to find the total horizontal displacement of the ball ( I posted how to do so in your other thread ).

With this in mind, you know exactly how far away the cart will need to be from the building for the ball to land inside of it.
 
  • #3
I too did it that way. But the answer needs a 'h'. Like the question says.
 
  • #4
judas_priest said:
I too did it that way. But the answer needs a 'h'. Like the question says.

Express your answer in terms of some or all of the variables h, v1, v2 and g

I don't see how the height of the building is relevant in this case. The height of the building would be used to calculate the total time the ball was in the air.
 
  • #5
judas_priest said:
x/v1 = d-x/v2.

This is one equation and two unknowns. You need another equation for a definite solution. Think how the height affects the motion.
 

1. What is a projectile?

A projectile is any object that is thrown, launched, or otherwise propelled through the air. It follows a curved path due to the forces of gravity and air resistance.

2. How does a projectile move?

A projectile moves in a parabolic path, meaning it follows a curved trajectory. This is due to the combination of its initial velocity and the constant acceleration of gravity.

3. What is a cart?

A cart is a small, wheeled vehicle used to transport goods or people. It typically has four wheels and can be pushed or pulled by a person or animal, or propelled by an engine.

4. How are a projectile and a cart related?

A projectile can be launched from a cart, for example, in a slingshot or cannon. The cart provides a stable platform for the projectile to be launched from and can also be used to adjust the direction and angle of the launch.

5. What are some real-life applications of projectiles and carts?

Projectiles and carts are used in many different industries and activities. Some examples include launching fireworks, throwing a ball in sports, firing bullets from guns, and transporting goods in warehouses or factories.

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