Pulley/Rotational Torque Problem

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The discussion revolves around solving a physics problem involving two blocks and a pulley, focusing on the concepts of acceleration, tension, and rotational inertia. The heavier block falls a distance of 81.4 cm in 2.59 seconds, leading to questions about the block's acceleration, the tensions in the cord supporting each block, the pulley's angular acceleration, and its rotational inertia. Participants express confusion about how to approach the problem, particularly regarding the correct formulas for calculating acceleration and torque. Key suggestions include using kinematic equations for linear motion and torque equations for rotational motion. Understanding the relationship between linear and angular quantities is essential for solving the problem effectively.
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Homework Statement


In Fig. 11-42, one block has a mass M = 500 g, the other has mass m = 460 g, and the pulley, which is mounted in horizontal frictionless bearings, has a radius of 5.00 cm. When released from rest, the heavier block falls 81.4 cm in 2.59 s (without the cord slipping on the pulley).

(a) What is the magnitude of the block's acceleration?

(b) What is the tension in the part of the cord that supports the heavier block?

(c) What is the tension in the part of the cord that supports the lighter block?

(d) What is the magnitude of the pulley's angular acceleration?

(e) What is its rotational inertia?
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The Attempt at a Solution



I am completely confused and I don't even know how to start this problem. Please help!

I tried doing .814=1/2a*2.59^2 to find a and it is wrong. :(
 
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It is a rotational motion problem because of the inertia of the pulley.
Use torque = (moment of inertia)*(angular acceleration)
 
How do I find the magnitude of the block's acceleration?

I am pretty sure it has something to do with the heavier block falling .814 meters in 2.59 seconds
 
Use an accelerated motion formula such as d = Vi*t + .5a*t^2
 
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