Question on speed and velocity

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To determine the depth of the well, the total time of 4 seconds is divided into two parts: T1, the time for the stone to fall, and T2, the time for the sound to travel back up. The velocity of sound is given as 350 m/s. By using the equation for distance (depth = velocity × time), the depth can be calculated by solving the equations for T1 and T2. The discussion encourages further questions for clarification on the problem-solving approach.
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a stone is dropped in a well is heard to hit the water after 4 sec what will be the depth of the well if the velocity of sound is 350m/s ?


3. the time taken by stone to reach the water surface is T1 and the time taken by the sound to reach out is T2 now T1+T2 = 4 sec.
thats all i could do
 
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You only need to change 3.5 s in the other question with 4.0 s in your task :)

You are welcome to ask if you wonder how I did something there...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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