The 1 inch rule of thumb is strictly a ball park rule I made up. I do not have the time to tweak the race car to be perfect nor the dollars to buy/fabricate the goodies needed to make it perfect.
RC movement to the left or right will add downforce or take away down force on the right front tire. One inch migration will not hurt us and depending upon which way it goes may even help.The formula car we run has 2 inch RC height centerline and dropped to .9”, ran great.Assume a 2800 pound late model, 112” wheelbase, 66” track width, Center of Gravity (CG) = center of gravity and is 13” height.
If we have the Roll Center located in the centerline of the car, 66” track width, RC is 33” from each tire centerline.This 2800 pound car has 56% left side weight. Subtract the unsprung weight and we get 2100 pounds sprung weight. I am assuming things are pretty symmetrical so we will use 56% of this unsprung weight or 1,175#.If the RC was centered it would be located 33” from each front tire centerline and theoretically, we have ½ of the 1,175# or 587# left side sprung weight pivoting on the roll center and going to the right side slamming on the tire. (If the RC is located to the right by 3” we now have a lever between the RC to the tire centerline 3” longer on the left side and 3” shorter on the right side.
36/66= 55% so in effect we have increased lever by 5%. Now we have 55% of the left side inertia force thru the RC planting the right front tire.
55% is 646# so you get 60 # additional down force.Now add an inch of offset to the right 37/66= 56% and this adds 12 pounds. The point is we need to use body roll to create down force (not applicable on BBSS set ups). If we get too aggressive with the RC offset we start to lift the left front tire.So far this is all speculation. Let’s plug in some real numbers.
Weight Transfer due to body roll
First of all, by now, you know I hate the term “weight transfer” but since I poached the illustration off of
http://www.autozine.org I will use it since they did a great job explaining it.In this example Weight is both sprung and unsprung weight.Lateral displacement of the CG is d. In this case, d = CG height in inches x sin of roll angle. Sin of 3° degrees is .052, sine of 5 ° is .088 sine of 10° is .173 and CG height is 13”If this racecar rolls over 3° we have .052 x 13 = 0.676Weight transfer to the outside wheel is (Weight x (RC location + d)) / track width2800# x (33” + 0.676) or 2800 x 33.676 = 94,29394,293 / 66” = 1,429# on outside wheelsCouple of things about this drill, folks. The Roll Center is assumed to be on the ground. Note the fact that we use the Sine of the angle of roll to find the additional length of the lever arm and add it to the RC to tire centerline lever length.Compare this to the Race car with centered roll center and no ° roll.2800 x 33 /66 = 1400 – conclusion, 3° roll gets you 30 pound down force, big deal (actually we should do the math right and figure exact RC location to get the true picture but hang with me here..)When we offset the RC to the right 3 inch and calculate
2800 x 36 / 66 = 1527 poundsAdd in 3° body roll and we get 1,555 poundsAdd 5° roll and we get 1,575#
Just for kicks that super dirt late model with 4 inch offset and 10 ° roll
2800 x (37 + (13 x .173)) = 2800 x (37 + 2.49) = 2800 x 39.49= 1,675#
What this tells us is the Roll Center location is important. One inch movement won’t hurt too much.