- #1
eridanus
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A capacitor, a resistor, and another capacitor is connected in series. The first capacitor, C_1, has an initial charge of Q_0, and C_2 is initially uncharged. The switch is flipped at t=0, what is the charge on each capacitor as a function of time?
So I thought
[tex]
Q_1 = Q_{0}e^{-t(C_{1}+C_{2})/RC_{1}C_{2}}
[/tex]
[tex]
V_1 = Q_{0}e^{-t(C_{1}+C_{2})/RC_{1}C_{2}}/C_{1}
[/tex]
[tex]
Q_2 = C_{2}/C_{1}(Q_{0}e^{-t(C_{1}+C_{2})/RC_{1}C_{2}})(1-e^{-t(C_{1}+C_{2})/RC_{1}C_{2}})
[/tex]
but this is apparently wrong
where am I messing up?
thanks.
So I thought
[tex]
Q_1 = Q_{0}e^{-t(C_{1}+C_{2})/RC_{1}C_{2}}
[/tex]
[tex]
V_1 = Q_{0}e^{-t(C_{1}+C_{2})/RC_{1}C_{2}}/C_{1}
[/tex]
[tex]
Q_2 = C_{2}/C_{1}(Q_{0}e^{-t(C_{1}+C_{2})/RC_{1}C_{2}})(1-e^{-t(C_{1}+C_{2})/RC_{1}C_{2}})
[/tex]
but this is apparently wrong
where am I messing up?
thanks.
Last edited: