A capacitor, a resistor, and another capacitor is connected in series. The first capacitor, C_1, has an initial charge of Q_0, and C_2 is initially uncharged. The switch is flipped at t=0, what is the charge on each capacitor as a function of time?(adsbygoogle = window.adsbygoogle || []).push({});

So I thought

[tex]

Q_1 = Q_{0}e^{-t(C_{1}+C_{2})/RC_{1}C_{2}}

[/tex]

[tex]

V_1 = Q_{0}e^{-t(C_{1}+C_{2})/RC_{1}C_{2}}/C_{1}

[/tex]

[tex]

Q_2 = C_{2}/C_{1}(Q_{0}e^{-t(C_{1}+C_{2})/RC_{1}C_{2}})(1-e^{-t(C_{1}+C_{2})/RC_{1}C_{2}})

[/tex]

but this is apparently wrong

where am I messing up?

thanks.

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# Homework Help: RC Circuit

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