RC DC Series and Parallel Circuit

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DeadFlower
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Hi!

Homework Statement



Circuit diagram for Figure 1.3: a 28 V battery E feeds a 6 Ω resistor R1, then capacitors C1 (12 µF) and C2 (24 µF) in parallel, then a 18 Ω resistor R2 back to the battery.

Homework Equations



V = IR
Kirchhoff Current and Voltage Law.

The Attempt at a Solution



I am facing difficulty with this RC circuit.
I tried looking up solutions but all I could find were either exclusively series or parallel.

My first guess was to take Total Current = 28/(6+18). However, that ended up being wrong.
I worked backwards from the answer provided and realized that Current through R2 = 28/(6+18) instead of what I thought earlier. However, I am unable to relate this to any of the formula I can find.I would be a great help if someone were able to explain to me how to arrive and the solutions to the question.
Thanks.
 
Attachments
  • Circuit diagram Figure 1.3: 28 V battery E in series with R1 = 6 Ω, feeding a parallel branch of C1 = 12 µF and C2 = 24 µF, then R2 = 18 Ω back to the battery.
    RC DC.JPG
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DeadFlower said:
Hi!

Homework Statement



Circuit schematic labelled Figure 1.3: 28 V battery in series with R1 = 6 Ω, then C1 = 12 µF and C2 = 24 µF in parallel, with R2 = 18 Ω on the right branch; question parts (a) charge on C1 and (b) energy stored in C2.



Homework Equations



V = IR
Kirchhoff Current and Voltage Law.


The Attempt at a Solution



I am facing difficulty with this RC circuit.
I tried looking up solutions but all I could find were either exclusively series or parallel.

My first guess was to take Total Current = 28/(6+18). However, that ended up being wrong.

How did you proceed from here?

DeadFlower said:
I worked backwards from the answer provided and realized that Current through R2 = 28/(6+18) instead of what I thought earlier. However, I am unable to relate this to any of the formula I can find.


I would be a great help if someone were able to explain to me how to arrive and the solutions to the question.
Thanks.

Does any current flow through the capacitors after reaching the equilibrium voltage?
The "total current" is the same as the current through either R2 and R1.

ehild
 
Can you calculate the voltages across the capacitors?
 
ehild said:
How did you proceed from here?



Does any current flow through the capacitors after reaching the equilibrium voltage?
The "total current" is the same as the current through either R2 and R1.

ehild

Oh my. It was a mathematical error on my part. I deeply apologise.

After taking Total Current = V/R= 28/(6+18) = 1r1r6 A
Voltage across R1 = IR = 1r1r6 * 6 = 7 V
Therefore voltage across C1 + C2 = 28 - 7 = 21 V
Capacitance total = (1/12 + 1/24)^-1 = 8 μF
Therefore Charge across C1 and C2 = CV = (8*10^-6)(21) = 168 μC (FOUND)

However there is one thing I would like to ask.
So, this means that no current flows through the capacitors?
 
DeadFlower said:
However there is one thing I would like to ask.
So, this means that no current flows through the capacitors?

It flows at the beginning when the circuit is connected. After a while, the capacitors are charged, till the voltage gets the same across them as the voltage across R2. After that, no more potential difference to drive charges to the capacitor plates, so no current flows after the steady state is settled.


ehild
 
ehild said:
It flows at the beginning when the circuit is connected. After a while, the capacitors are charged, till the voltage gets the same across them as the voltage across R2. After that, no more potential difference to drive charges to the capacitor plates, so no current flows after the steady state is settled.


ehild

Ahhh, I understand now. Thanks!

Thread closed then :)