Regarding efficiency of heat engines

AI Thread Summary
The discussion revolves around the calculation of engine efficiency using two different methods: one based on net work done and heat absorbed, and the other using the Carnot efficiency formula. The user reports discrepancies between the results obtained from these two approaches. Participants emphasize the importance of providing complete problem statements and using the Homework Template for clarity. There is a suggestion for the user to share their calculations to facilitate better assistance. The conversation highlights the need for thoroughness in problem-solving to avoid misunderstandings.
Nitin Gupta
Messages
9
Reaction score
0
I tried to calculate the efficiency of a engine using the formula :
Efficiency = (Net Work Done) / (Heat absorbed)

And then I tried to calculate the efficiency of respective Carnot engine by two ways :
1) Efficiency = (Net Work Done) / (Heat absorbed)
2) Efficiency = 1 - (Temperature Lowest / Temperature Highest)

But the efficiency I am getting by the two methods different.How is this possible?
 
Physics news on Phys.org
Nitin Gupta said:
I tried to calculate the efficiency of a engine using the formula :
Efficiency = (Net Work Done) / (Heat absorbed)

And then I tried to calculate the efficiency of respective Carnot engine by two ways :
1) Efficiency = (Net Work Done) / (Heat absorbed)
2) Efficiency = 1 - (Temperature Lowest / Temperature Highest)

But the efficiency I am getting by the two methods different.How is this possible?

Beats me.

This is exactly why the PF Rules state that the Homework Template should be filled out completely, so that HW helpers don't have to extract information piece by piece from users.

Please use the HW template and post the complete problem statement you are working on along with your work which has led to an irreconcilable result.
 
  • Like
Likes Nitin Gupta
SteamKing said:
Beats me.

This is exactly why the PF Rules state that the Homework Template should be filled out completely, so that HW helpers don't have to extract information piece by piece from users.

Please use the HW template and post the complete problem statement you are working on along with your work which has led to an irreconcilable result.

Sorry for the extremely late reply...check this out...here is what I attempted...
 
Sorry, it looks like your work didn't make it into your post. :frown:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top