A uniform rod is pivoted at its center and a small weight of mass M = 5.29 kg is rigidly attached to one end. You may neglect the size of the weight and assume it is located right at the end of the rod. Suppose that the rod has length L = 6.8 m and mass mrod = 10.6 kg. Suppose also that there are no external forces applied (i.e. Fh = Fv = 0). The system is released from rest at the q = 37° angle. What is the angular acceleration just after it is released? i did the following; net torque = I * alpha find I of the rod+weight system. and net toque, and solve for alpha but i have a question regarding the force of the rod itself... i've been told to treat the rod as if all its mass were concentrated at its center of mass. but is that with or without the weight attached to it? i mean, w/o the weight, the center of mass of the rod is at the axis point., thus no torque on that point.