- #1
psycovic23
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I have a problem that I'm not sure how to approach. "If the shear stress in steel exceeds about 4.00 x 10^8 N/m^2, the steel ruptures. Determine the shearing force necessary to (a) shear a steel bolt 1.00 cm in diameter and (b) punch a 1.00 cm diameter hole in a steel plate .500 cm thick.
I think I got A right (3.14x10^4, right?), but I'm stuck on B. I'm trying to use
[tex]\frac{F}{A} = S \frac{\Delta x}{h}[/tex]
but I don't know what to use for h. So far, I'm solving for F, A=pi*.005^2, S = 8.4x10^10, delta x = .500 cm, but I don't know what H is. Any ideas?
I think I got A right (3.14x10^4, right?), but I'm stuck on B. I'm trying to use
[tex]\frac{F}{A} = S \frac{\Delta x}{h}[/tex]
but I don't know what to use for h. So far, I'm solving for F, A=pi*.005^2, S = 8.4x10^10, delta x = .500 cm, but I don't know what H is. Any ideas?
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