Snell's law experiment with glass block

AI Thread Summary
The discussion centers on a student's experiment to determine the refractive index of a glass block using Snell's law. The student measures angles of incidence and refraction, identifying the angle of incidence as the independent variable and the angle of refraction as the dependent variable. Safety precautions include ensuring the experiment is conducted in a dark room to avoid stray light interference. Concerns about measurement accuracy arise from potential issues with the thickness of light beams and the impact of different light wavelengths on refraction angles. The conversation also touches on the use of lasers for precise measurements and the relevance of the Sellmeier equation in understanding the relationship between wavelength and refractive index.
Barclay
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Homework Statement


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A student wants to find the refractive index of a rectangular block of glass. He draws around the block and marks the position of a ray of light that travels through the block. With the block removed, the student can draw in a normal line and then measure the angle of incidence and the angle of refraction. The student repeats this process for different angles of incidence. His measurements are shown in the table.

Angle of incidence Angle of refraction

10° ...... 6.5°
20° ........ 13°
30° .......20°
40° ....... 25°
50° .......32°
60° ........35°

Homework Equations


Snells law
Refractive index = (sin i / sin r)


3. QUESTIONS & the attempt at a solution

(i)
Draw a diagram to show the measurements the student needs to make.

I'm okay with this part

(ii) What was the independent variable in this investigation? What was the dependent variable?

Independent variable is the angle of incidence (because it is the one that can be varied).
Dependent variable is the angle of refraction (because it is dependent on the angle of incidence).

(iii) What, if any, safety precautions should be taken if this experiment is carried out in the classroom?

Ensure that the room is dark for there is no stray light that might make the ray of light difficult to see.

(iv) Describe two possible reasons the measurements may not be completely accurate.

The beams of light may be too thick and splayed so measurements of angles will be inaccurate.

(v) What difference would it make to the results if light of a different color was used in the experiment?

The wavelength will be different so the angle of refraction will be different.
What formula links the angle of refraction and the wavelength?Thanks
 
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Hi Barclay

Barclay said:
(i) Draw a diagram to show the measurements the student needs to make.

I'm okay with this part

When doing homework problems on the forum or elsewhere ... it is a good thing to show your working diagrams etc
to make sure the student has the correct understanding
Barclay said:
(iii) What, if any, safety precautions should be taken if this experiment is carried out in the classroom?

Ensure that the room is dark for there is no stray light that might make the ray of light difficult to see.

That's not really a safety issue is it ? ... that's more of an experiment contamination issue :wink:
when speaking of safety precautions, I would expect them to be referring to student safety as they did the experiment

so in that light, consider the light sources, that can produce a narrow beam, that you may use for this experiment
one would require safety eyewear and one wouldn't ... what would they be ?

Barclay said:
(v) What difference would it make to the results if light of a different color was used in the experiment?

The wavelength will be different so the angle of refraction will be different.
What formula links the angle of refraction and the wavelength?

you already know that, you listed it near the top of your post :smile:
so write it out in full, and refer to the wiki page on it if you are not sure Dave
 
Last edited:
Hello, I don't know how to paste my own pictures on here so I've got some from the internet:https://upload.wikimedia.org/wikipedia/commons/8/85/Refraction_photo.png
refind.gif
 
davenn said:
so in that light, consider the light sources, that can produce a narrow beam, that you may use for this experiment
one would require safety eyewear and one wouldn't ... what would they be ?

A laser light can be used such as from a laser pen or a laser spirit level (used by builders)
Regarding a formula linking wavelength and refractive index I found this

snells_law.png
 
Last edited:
Barclay said:
What formula links the angle of refraction and the wavelength?
Do a search on the Sellmeier equation.
Barclay said:
Hello, I don't know how to paste my own pictures on here so I've got some from the internet:
Upload a file from your machine. Use the UPLOAD icon at the lower right of the edit panel.
 
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Likes davenn
Barclay said:
(ii) What was the independent variable in this investigation? What was the dependent variable?

Independent variable is the angle of incidence (because it is the one that can be varied).
Dependent variable is the angle of refraction (because it is dependent on the angle of incidence).

Have I got the independent and dependent variables mixed up?

I'm concerned because I read somewhere that : x-axis = independent variable y-axis = dependent variable.

But later in the question in the book it says: Draw a graph of sin i (y-axis) against sin r (x-axis).
gneill said:
Do a search on the Sellmeier equation.
Have seen it but it's beyond High School level. Way above my needs. Thanks
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

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