Solving a Belt and Pulley Question Using Simple Equations

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The discussion revolves around solving a belt and pulley problem using the equation (g(M-m))/(M+m) to find the magnitude of force, which resulted in 6 kN. The original poster questions the validity of their approach, noting difficulty in finding similar examples online. Respondents express confusion about the equation's origin and suggest calculating the net force on the pulley by vectorially adding tension forces instead. Clarification is sought regarding the masses involved and their relevance to the problem. The conversation emphasizes the need for a clearer understanding of the forces at play in the pulley system.
Idrees27
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Hi guys,

I am working on a simple belt and pulley question, as pictured below.

4a7b0128.jpg


To find the magnitude, I used the following equation:

(g(M-m))/(M+m)

So,

9.81(2500-600)/(2500+600) = 6.01 - Answer = 6kN

Is this correct, or am I doing it totally wrong? I have searched for the same question but didn't find any like this with a single pulley, all other examples seem to show 2 pulleys.

Any help would be greatly appreciated.
 
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Idrees27 said:
To find the magnitude, I used the following equation:

(g(M-m))/(M+m)
I don't understand that expression. Where did you get it? (Are m and M masses?)

In any case, why not just find the net force on the pulley due to the belt tension? Add up those tension forces vectorially.
 
Doc Al said:
I don't understand that expression. Where did you get it? (Are m and M masses?)

In any case, why not just find the net force on the pulley due to the belt tension? Add up those tension forces vectorially.
Yes, they are masses. That's a formula I found via Google.

How would you attempt the whole question?
 
Idrees27 said:
Yes, they are masses. That's a formula I found via Google.
Masses of what? How is that relevant?
How would you attempt the whole question?
Do as I suggested in my last post.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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