Solving for the Direction of an Electron in a Magnetic Field

AI Thread Summary
An electron moving at 9.50 x 10^5 m/s in a 4.4 T magnetic field experiences an upward force of 3.40 x 10^-14 N. The relevant equation is F=qB(vsin θ), which leads to solving for sin θ. The discussion indicates that there should be two angles measured clockwise from south. One participant calculated an angle of 2.91 degrees but questioned its accuracy, suggesting a potential oversight in the solution process. The conversation emphasizes the need to find both angles correctly.
phy112
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Homework Statement



An electron moves with speed 9.50 105 m/s in a uniform magnetic field of 4.4 T, pointing south. At one instant, the electron experiences an upward magnetic force of 3.40 10-14 N. In what possible directions might the electron be moving at that instant? Give your answers as angles clockwise from south (from 0° to 360°), in increasing degrees.

Homework Equations



F=qB(vsin theta)

The Attempt at a Solution


I keep trying to plug all the knowns into this equation but i cannot seem to find the right answer.
3.4e-14=(1.6e-19)(4.4)(9.5e5sin theta) and find inverse.

the 2 answers should be clockwise from south
 
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Hi phy112! :smile:

(have a theta: θ :wink:)
phy112 said:
3.4e-14=(1.6e-19)(4.4)(9.5e5sin theta) and find inverse.

the 2 answers should be clockwise from south

just solve for sinθ … should give you two answers :smile:
 
i did that and got an angle of 2.91. that isn't right though. i am wondering if there is another step I am missing.
 
You should have got two angles.
 
arent the two angles the same??
 

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