Some serious help needed in thermodynamics

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The discussion centers on a thermodynamics problem involving an insulated piston-cylinder assembly containing air and nitrogen. The initial conditions for both gases are provided, and the task is to determine the final pressure of nitrogen, heat transfer, work done on the air, and the value of n for the compression process. The analysis indicates that the process is adiabatic, leading to calculations for the final pressure of nitrogen at 68.27 kPa and work done on nitrogen at 8.03 kJ. There is a concern about the heat transfer calculation, as it appears to underestimate the energy interactions between the gases, particularly regarding the work done and heat exchange. The discussion highlights the importance of correctly applying thermodynamic principles to ensure accurate results.
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Homework Statement


An insulated piston-cylinder assembly contains air and nitrogen separated by a highly conducting partition. Accordingly, the temperatures of the two gases may be assumed to be equal at all times. Initial Conditions of air are 0.3m3,101kPa, 30C and of nitrogen 0.13,101kPa,30C. Air is compressed 'till the temperature reaches 200C. Determine:
1)The final pressure of nitrogen
2) The amount of heat transfer between them
3) The work done on the air
4)The value of n if the compression of air follows PVn= Constant.


Homework Equations



Ideal gas law, PVk=Constant
Q-W=U

The Attempt at a Solution


Since the piston is insulated, the side containing nitrogen has no net transfer of heat towards the surroundings i.e. adiabatic process.
For Nitrogen \gamma = \frac{c_p}{c_v}= \frac{1.039}{0.743}
P_1V_1^{\gamma}=P_2V_2^{\gamma}

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

Combing these two equations I get:

T_1V_1^{\gamma -1}=T_2V_2^{\gamma-1}
\Rightarrow V_2=\frac{T_1}{T_2}V_1^{\gamma-1}
V_2=\frac{273+30}{273+200}(0.3)^{1.398-1}
V_2=0.397m^3

P_1V_1^{\gamma}=P_2V_2^{\gamma}
\Rightarrow P_2=P_1(\frac{V_1}{V_2})^{\gamma}=68.27kPa

2) Work done on N2

W= \frac{P_2V_2-P_1V_1}{1- \gamma}=8.03kJ

(this means that the work done by the air on the N2 is also 8.03kJ)

Now \delta U=mc_v \delta T[/tex]<br /> <br /> m=\frac{P_2V_2}{RT_2}<br /> <br /> I was given M=25kg/kmol and I know that MR=r where r is the universal gas constant (8.3143kJ/kgK)<br /> such that R=8.3143/(28x10^-3)=296.94kJ/kg<br /> <br /> \delta U= 0.00019kJ<br /> (I think my units may be wrong here)<br /> <br /> So then by the 1<sup>st</sup> law of thermodynamics, the heat transfer between air and nitrogen is <br /> Q=0.00019+8.03=8.03019kJ.<br /> <br /> This somehow seems wrong to me.
 
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I haven't checked though your entire derivation, but from reading the problem statement it seems that:

For the nitrogen, there is heat transfer (from the compressed air), but no work (volume=constant).

For the air, there is both work (from compression) and heat transfer (to the nitrogen).

The energy added to the whole system is the work done by the piston, so you can figure out what that is from the temperature rise and amount of each gas present.

The energy added to the nitrogen is the heat exchanged between the two gases. One can figure out what that is from the temperature rise and the amount of nitrogen present.
 
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