Speed of proton as fraction of c

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Homework Help Overview

The discussion revolves around finding the speed of a proton as a fraction of the speed of light (c) and its momentum, given a specific kinetic energy of 1000 MeV. The problem involves concepts from relativistic physics, particularly kinetic energy and momentum equations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the kinetic energy formula but expresses uncertainty about the results, specifically regarding the expected speed of 0.875c. Other participants question the correctness of the kinetic energy formula being used and suggest a potential confusion between total energy and kinetic energy.

Discussion Status

Participants are actively engaging in clarifying the definitions of kinetic energy and total energy in the context of relativistic physics. Some guidance has been offered regarding the correct formulation of kinetic energy, but there is no explicit consensus on the original poster's approach or the correct formula to use.

Contextual Notes

There is a noted confusion regarding the distinction between total energy and kinetic energy, which may be affecting the calculations. The original poster's reference to their textbook is also highlighted as a potential source of misunderstanding.

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Homework Statement



Find the speed (as a decimal fraction of c) and momentum of a proton that has a kinetic energy of 1000MeV. The proton mass is 1.673x10-27kg, or 938 MeV/c2.

Homework Equations



KE= (1/2)mv2
KE= \gammamc2
p=mv
\gamma=1/(sqrt(1-(v2/c2)))

The Attempt at a Solution



I'm not too sure about the KE, it's supposed to be 0.875c but I can't get that value...
I've been solving for gamma and then solving for u, but I get outrageous values.
 
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Your formula for the kinetic energy is wrong. That's probably why you're getting non-sensical results.
 
Really? It's what our book gives us :/ Mind telling me what I should be using?
 
I doubt that's what your book says. It's more likely you're just confusing the total energy with the kinetic energy. The total energy of an object of rest mass m is given by E=\gamma mc^2. Note when the object isn't moving and therefore has no kinetic energy, you still have \gamma=1 and E_0=mc^2. This energy E0 is called the rest energy; it's the energy an object has just because it has mass. The kinetic energy of an object is the amount of energy in excess of the rest energy. Since the total energy is equal to E=\gamma mc^2 and the rest energy is E_0=mc^2, the kinetic energy is equal to K=E-E_0=(\gamma-1)mc^2.
 

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