Static friction on objects resting on a rotating surface

AI Thread Summary
The discussion centers on the forces of static friction acting on a brick resting on a rotating disc. It is established that static friction provides the necessary centripetal force to keep the brick moving in a circular path. There is confusion regarding whether static friction also acts tangentially to prevent slipping, as the brick maintains a constant speed. It is clarified that static friction can act without causing movement, and during the initial rotation, kinetic friction may have played a role in aligning the brick's speed with that of the disc. Ultimately, the forces involved ensure that the brick does not slip tangentially as the disc rotates.
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Homework Statement



Suppose I have a brick that's sitting at the edge of a disc that is rotating clockwise with uniform circular motion.

I what direction(s) are the forces of static friction acting?

Homework Equations



a = v^2/r


The Attempt at a Solution



I know that a centripetal force from static friction acts on the brick to keep it moving in a circle along with the disc. Is there also a static friction force acting on the brick tangentially in a counterclockwise direction to prevent the disc from slipping under the brick?
 
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The brick is moving in a circle with constant speed. What would happen to the
speed of the brick if there was a friction force that wasn't perpendicular to the direction of the velocity?
 
No.

ehild
 
If a force were applied tangentially, the brick would move in non-uniform circular motion (either accelerating or decelerating tangentially).

The trouble I have is with the fact that the force in question is friction; and that static friction can act without causing an object to move.

I'm finding it hard to picture why the disc doesn't slip (tangentially) under the brick, if static friction only points towards the centre of the disc.
 
A body performs uniform circular motion under the effect of the appropriate centripetal force. If the brick moves already together with the disk then the only in-plane force points towards the centre of the disc and equals to mv^/R.

When the disk was in rest and started to rotate, the brick might have slipped at the beginning till the kinetic friction had accelerated it to the velocity equal to its place on the disk. At this starting period, the force had both radial and tangential components.

ehild
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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