What is the formula for tension at various angles in a constrained mass system?

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The discussion centers on deriving the formula for tension, denoted as f_tension, acting on a mass m_2 constrained to move along a track, influenced by a magnetic force f_mag from another mass m_1. The problem involves a near-massless rod connecting m_2 and m_1, with the angle θ between the rod and the horizontal affecting the tension. While specific cases for θ at 0 and 90 degrees are provided, the user struggles to find a general formula for f_tension for angles between 0 and 90 degrees. The conversation highlights the importance of trigonometry and vector decomposition in solving the problem, with suggestions to draw free body diagrams for clarity. The need for a mathematical representation of how tension varies with angle is emphasized.
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I have been struggling with this problem for years and never have found an answer to it anywhere on the web or in textbooks. And I can’t derive the formula for it.

Suppose we have a mass designated as ##m_2##. This mass is constrained to move with one degree of freedom along a linear track. We assume no friction between ##m_2## and the track. The track is rigidly attached to the earth. We define the motion of ##m_2## to be along the y-axis.

There is a near-massless aluminum rod attached at one end to ##m_2##. At the other end of the rod is attached a magnet with mass ##m_1##. A person holds another magnet near ##m_1##, such that there is a magnetic force experienced by ##m_1## in the radially outward direction. We designate this force on ##m_1## as ##f_{mag}##. Because of this ##f_{mag}##, ##m_2## accelerates in the positive y-direction along the linear track.

The person hovers over the Earth in some kind of spacecraft or whatever, so there is no contact forces between the Earth and the bottom of the shoes of the person. And with this spacecraft , the person is able to keep the distance between the two magnets constant and keeps up with the accelerating ##m_2##, such that ##f_{mag}## remains constant.

We define the angle ##\theta## as the angle between the rod and the horizontal x-axis.

Here is my conundrum. I want to know the tension force, designated ##f_{tension}## acting on ##m_2## for all angles of the rod.

I know for the special case where ##\theta## is equal to 90 degrees, it would simply be:

$$f_{tension} = \frac {m_2} {m_1 + m_2} f_{mag}$$

And for ##\theta## equal to 0 degrees, it would be:

$$f_{tension} = \frac {m_{earth}} {m_1 + m_{earth}} f_{mag}$$

Where, ##m_{earth}## is the combined mass of the Earth and ##m_2##.

But I cannot figure out the formula for ##f_{tension}## for any angle ##\theta## between 0 and 90 degrees. Can someone help me out with this?
 
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I can't help you with the problem but I strongly suggest that for clarity you draw a diagram of exactly what you mean.
 
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Here is an attached drawing.
 

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Two concepts that you'll need here:
1) Trigonometry. Are you familiar with the ##\sin## and ##cos## functions?
2) Decomposing vectors into components.
 
Nugatory said:
Two concepts that you'll need here:
1) Trigonometry. Are you familiar with the ##\sin## and ##cos## functions?
2) Decomposing vectors into components.

I am familiar with both. However, I can't conceptualize and put it into mathematics how the tension force changes as a function of the angle. For example, let's say ##\theta## is 45 degrees. It seems to me that the tension force would by a "hybrid" force, a function of ##m_1## interacting with ##m_2## and ##m_{earth}## along the x-axis, and ##m_1## simultaneously interacting with just ##m_2## along the y-axis. Because of this, I can't decide how to set up the trig equations.
 
Have you drawn free body diagrams for m1 and m2?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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