Thermal Stress (Thermodynamics)

AI Thread Summary
The discussion centers on the equation for thermal stress in materials, specifically how to derive the stress when a rod's length is allowed to change with temperature. The initial equation, F/A = -YαΔT, describes the stress needed to maintain a constant length as temperature varies. When the length is permitted to change by ΔL, the stress can be expressed as F/A = Y((ΔL/L₀) - αΔT), incorporating the original length, cross-sectional area, and material properties. Participants express confusion about how changes in length affect volume and area, and how these changes influence stress calculations. Clarification on these relationships is sought to better understand the derivation of the stress equation.
Luongo
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1. Equation F/A=-Y\alpha\DeltaT (thermal stress) gives the stress required to keep the length of a rod constant as its temperature changes. Show that if the length is permitted to change by an amount \DeltaL when its temperature changes by \DeltaT, the stress is equal to F/A = Y((\DeltaL/L_{}0)-\alpha\DeltaT) where F is the tension on the rod, L(naut) is the original length of the rod, A its cross-sectional area, alpha its coefficient of linear expansion, and Y its Young's modulus.


i don't know where to start can somebody help? this thermal stress is stressing me out
 
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Luongo said:
1. Equation F/A=-Y\alpha\DeltaT (thermal stress) gives the stress required to keep the length of a rod constant as its temperature changes. Show that if the length is permitted to change by an amount \DeltaL when its temperature changes by \DeltaT, the stress is equal to F/A = Y((\DeltaL/L_{}0)-\alpha\DeltaT) where F is the tension on the rod, L(naut) is the original length of the rod, A its cross-sectional area, alpha its coefficient of linear expansion, and Y its Young's modulus.


i don't know where to start can somebody help? this thermal stress is stressing me out
If the length changes by dL what does the volume change by? So what does the area, A, change by? How does this affect the stress, F/A?

AM
 
Andrew Mason said:
If the length changes by dL what does the volume change by? So what does the area, A, change by? How does this affect the stress, F/A?

AM


if the length changes the area would increase and the pressure would decrease. I'm not sure how you "Show This" though
 
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