Torque and Forces in Spool Movement: Solving for Net Torque and Static Friction

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The discussion focuses on calculating net torque and static friction in spool movement, emphasizing the relationship between forces in both the x and y directions. Key equations include net torque expressed as rTcos(theta) - RFs = 0, leading to the conclusion that r = R when static friction equals Tcos(theta). Participants are encouraged to visualize the problem and consider different axes for torque calculations, particularly suggesting moments about the point of contact with the ground for simplicity. A breakthrough occurs when it is clarified that the torque due to tension should be considered as Tr rather than Trcos(theta). The conversation highlights the importance of understanding rolling versus slipping dynamics in solving the problem effectively.
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Homework Statement
Problem in picture
Relevant Equations
Fnet=ma
Forces in the x direction: static friction left=Tcostheta to the right
Forces in the y direction: W= Normal force + Tsintheta
Net torque: rTcostheta-RFs=0

Fs=Tcostheta,
rTcostheta-R(Tcostheta)=0
rTcostheta=RTcostheta
r=R

Please help
 

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This is a multiple choice question, so try to use intuition about rolling vs slipping to eliminate answers. Look at each variable in turn: for instance what if r=R? Will it roll? Then think about theta...what if it is zero...90deg...
 
jaewonjung said:
Net torque: rTcostheta-RFs=0
Looks like you are taking moments about the centre of the cylinder. Think again about the torque due to T. Maybe draw a nice big picture, carefully.
(There is a better choice of axis for this problem.)
 
I solved it! The torque of the Tension is just Tr, not Trcostheta. Thanks for the help!
 
jaewonjung said:
I solved it! The torque of the Tension is just Tr, not Trcostheta. Thanks for the help!
Good.
Note that if you take moments about the point of contact with the ground instead it becomes a matter of simple geometry.
 
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