matthew77ask
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I got very confuse about this questions and really appreciate your help on this... many thanks in advance.
A tow truck of mass 1000kg is towing a car of mass 600kg and both are moving at a constant velocity of 60m/s. The total resistance to the motion is 4000N and half of this resistance acts on the car. What is the force exerted on the tow-truck by the car? (ans 2000N)
Steps taken.
Total mass = 1000 + 600 = 16000kg.
Since it is moving at constant velocity, a = 0
Hence Force = resistance force
16000a = 4000
a = 2.5 m/s2
Mass of car = 600 kg, ==> force by car = 600 x 2.5 = 1500N
Nett force on car = 1500 -2000 = -500 N
Mass of tow-truck = 1000kg ==> force by truck = 1500 x 2.5 = 2500N
Nett force on truck = 2500 - 2000 = 500N
I think I am wrong somewhere, but got confused and not sure where am I wrong?
Please help me... thanks
A tow truck of mass 1000kg is towing a car of mass 600kg and both are moving at a constant velocity of 60m/s. The total resistance to the motion is 4000N and half of this resistance acts on the car. What is the force exerted on the tow-truck by the car? (ans 2000N)
Steps taken.
Total mass = 1000 + 600 = 16000kg.
Since it is moving at constant velocity, a = 0
Hence Force = resistance force
16000a = 4000
a = 2.5 m/s2
Mass of car = 600 kg, ==> force by car = 600 x 2.5 = 1500N
Nett force on car = 1500 -2000 = -500 N
Mass of tow-truck = 1000kg ==> force by truck = 1500 x 2.5 = 2500N
Nett force on truck = 2500 - 2000 = 500N
I think I am wrong somewhere, but got confused and not sure where am I wrong?
Please help me... thanks