Transverse Waves- Verticle Rope

AI Thread Summary
The discussion focuses on analyzing the propagation of transverse waves in a vertically hanging rope. It is established that the wave speed is determined by the tension and mass per unit length, resulting in a speed of sqrt(y*g), which is independent of the rope's total mass and length. To achieve a wave speed equal to the speed of sound in air (330 m/s), the rope would need to be approximately 11,000 meters long. The user struggles with calculating the time for a wave to travel from the bottom to the top of the 3 m rope and back, expressing difficulty in relating known wave equations without additional parameters like wavelength or frequency. The thread highlights the complexities of wave dynamics in different orientations of ropes.
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Homework Statement


A heavy rope 3 m long is attached to the ceiling and allowed to hang freely. Let y = 0 denote the bottom end of the rope. To get started on this problem, imagine cutting the rope at an arbitrary value of y. Draw a free body diagram of each of the two pieces of rope to determine the tension at the point where the rope was cut.

3.1 Determine the propagation speed of transverse waves on the rope and show that this speed is independent of the rope's mass and overall length.


3.2 How long would the rope have to be in order for the maximum propagation speed to be equal to the speed of sound in air (which we will take to be 330 m/s)?


3.3 Calculate the time it takes for a transverse wave to travel from the bottom of the 3 m long rope to the top and then back to the bottom.


3.4 Compare this round-trip time to that for a horizontal rope with the same tension as the average tension of the vertical rope.



2. Homework Equations and

The Attempt at a Solution



All right, here's what I tried:

3.1 If you cut the rope at an arbitrary point y, you can get the tension by the gravitational force on that section of the rope, which would be y*g*mu, with mu being the mass per unit length of the rope. Since propagation speed is sqr(tension/mu), it cancels out to sqrt(y*g), not being dependent on the mass or the total length of the rope.

3.2 This one was easy, I just set 330 m/s to sqrt(y*g), and found y to be 1.1x10^4 m.

3.3 This is where I get stuck. All of the wave equations I know don't let me simplify this enough to be able to solve for T. I don't know the wavelength,amplitude or frequency, so how can I solve for the period?

I really appreciate any help! Thanks in advance :o).
 
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