Transverse Waves- Verticle Rope

AI Thread Summary
The discussion focuses on analyzing the propagation of transverse waves in a vertically hanging rope. It is established that the wave speed is determined by the tension and mass per unit length, resulting in a speed of sqrt(y*g), which is independent of the rope's total mass and length. To achieve a wave speed equal to the speed of sound in air (330 m/s), the rope would need to be approximately 11,000 meters long. The user struggles with calculating the time for a wave to travel from the bottom to the top of the 3 m rope and back, expressing difficulty in relating known wave equations without additional parameters like wavelength or frequency. The thread highlights the complexities of wave dynamics in different orientations of ropes.
bollocks748
Messages
10
Reaction score
0

Homework Statement


A heavy rope 3 m long is attached to the ceiling and allowed to hang freely. Let y = 0 denote the bottom end of the rope. To get started on this problem, imagine cutting the rope at an arbitrary value of y. Draw a free body diagram of each of the two pieces of rope to determine the tension at the point where the rope was cut.

3.1 Determine the propagation speed of transverse waves on the rope and show that this speed is independent of the rope's mass and overall length.


3.2 How long would the rope have to be in order for the maximum propagation speed to be equal to the speed of sound in air (which we will take to be 330 m/s)?


3.3 Calculate the time it takes for a transverse wave to travel from the bottom of the 3 m long rope to the top and then back to the bottom.


3.4 Compare this round-trip time to that for a horizontal rope with the same tension as the average tension of the vertical rope.



2. Homework Equations and

The Attempt at a Solution



All right, here's what I tried:

3.1 If you cut the rope at an arbitrary point y, you can get the tension by the gravitational force on that section of the rope, which would be y*g*mu, with mu being the mass per unit length of the rope. Since propagation speed is sqr(tension/mu), it cancels out to sqrt(y*g), not being dependent on the mass or the total length of the rope.

3.2 This one was easy, I just set 330 m/s to sqrt(y*g), and found y to be 1.1x10^4 m.

3.3 This is where I get stuck. All of the wave equations I know don't let me simplify this enough to be able to solve for T. I don't know the wavelength,amplitude or frequency, so how can I solve for the period?

I really appreciate any help! Thanks in advance :o).
 
Physics news on Phys.org
Just didn't want to get bumped off. :-)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top