Two forces at 45 pull an object distance of 14. What is work by both forces?

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SUMMARY

The work done by two forces of 7 N each, acting at a 45-degree angle, on an object moved a distance of 14 m is calculated using the formula W = F * d. The correct approach involves determining the resultant force using the Pythagorean theorem, yielding a force of approximately 9.9 N. The total work done is then calculated as W = 9.9 N * 14 m, resulting in 138.6 J. The initial calculation of 69.30 J is incorrect due to misapplication of the force components.

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What is the work done by the two forces together in moving an object a distance of d = 14 m as shown in the diagram? The magnitude of each force is 7 N.
 

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evan b said:
What is the work done by the two forces together in moving an object a distance of d = 14 m as shown in the diagram? The magnitude of each force is 7 N.

Separate the forces into components. What you are interested in are the force components in the direction that the block is actually moved.

W = f * d.
 
ya, so i found force by sqrt of 7^2 + 7^2. then i multiplied it by 7 and go 69.30 J. What am i doing wrong?
 
evan b said:
ya, so i found force by sqrt of 7^2 + 7^2. then i multiplied it by 7 and go 69.30 J. What am i doing wrong?

Isn't the distance it's moved 14?
(The sqrt of 98 looks ok for the force in the direction of motion.)
 

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