Understand Ohm's Law: Proportional Relationship Explained

  • Thread starter Thread starter Mrod777
  • Start date Start date
  • Tags Tags
    Law Ohm's law
AI Thread Summary
Ohm's Law defines the relationship between voltage, current, and resistance in an electrical circuit, stating that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R). The equation I = V/R illustrates this relationship, where an increase in voltage results in an increase in current, while an increase in resistance leads to a decrease in current. The discussion highlights the concept of proportionality, clarifying that direct proportion means both variables increase together, while indirect proportion indicates that one variable's increase results in the other's decrease. This understanding of proportional relationships is essential for grasping basic electronics principles. The explanation provided effectively addresses the inquiry about the proportional nature of Ohm's Law.
Mrod777
Messages
5
Reaction score
0
Ohm's law states that, in an electrical circuit, the current passing through a conductor between two points is directly proportional to the potential difference (i.e. voltage drop or voltage) across the two points, and inversely proportional to the resistance between them. The mathematical equation that describes this relationship is:

I = V/R
I realize this may be a basic question in electronics however I am looking at it in a new perspective, that of proportions.

Can someone please aide me in comprehending what is defined as (proportional) in this Law.
thanks
 
Physics news on Phys.org
The law was formulated as V across two points is directly proportional to the current I. The constant of proportionality was called the resistance R.
 
"Direct proportion" means that as one variable increases, the other increases (more voltage = more current).

"Indirect proportion" means that as one variable increases, the other decreases (more resistance = less current).
 
Thanks Noein your anwser explains what I wanted to know
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top